реальный вариант 1д 2023 12

Исполнитель Редактор def su(s): a=[int(i) for i in s] return sum(a) for n in range(4,10000): s='5' '2'*n while '72' in s or '522' in s or '2222' in s: s=('72','2',1) s=('522','27',1) s=('2222','5',1) if su(s)==63: print(n) break