We know the range of sin(x) is between -1 and 1, inclusively, but that's just with real numbers x. What if our input for the sine function is a complex number? In fact, we can derive the complex definition of sine from the Euler's formula and we can write sin(z) in terms of complex exponential (e^(iz)-e^(-iz))/(2i) and we will be able to solve sin(z)=2. 💪 Support this channel, This is my equation of the year in 2017. To see others, please check out here 👉 #equationoftheyear -ln(2 -sqrt(3)), Euler's formula: *Sorry I forgot the square root. |z| =sqrt(a^2 b^2) **Also, I should have written the horizontal axis as “Re“ and the vertical axis as “Im“ ***The last time I did complex analysis was back in 2012
Hide player controls
Hide resume playing